🚀 go-pugleaf

In article <KANZE.95Sep25163038@slsvhdt.lts.sel.alcatel.de> kanze@lts.sel.alcatel.de writes:

>Does this mean that you want the following to be illegal:
>
>        void f( int i ) ;
>        int i ;                 //  Illegal, since `i' from f-p still
>                                //  in scope.
>
>(I have no particular point of view concerning f-p scope, but I do
>want the above to be legal.)

Don't worry, it is.  I think you may have confused 'function prototype 
scope' with 'the scope of the function declaration'. (Which in this 
case is a prototype.)

The function declaration (prototype) declares 'f' as a 'function 
returning void'.  The declarator 'f' has file scope, just like the 
'i' in the _second_ line.

The scope of the 'i' in the parameter list is 'function prototype scope',
which ends at (in the words of the standard) "the end of the function 
declarator".  i.e. at the closing parenthesis of the function prototype.  
i.e. 

       void f( int i, int j ) ;
                   ^        ^
 start of scope of i(?)     end of scope of i / end of func'n proto. scope

-- 
 Ian Cargill
 Posting in comp.std.c is like running at high speed down a steep hill.
 It's not a matter of if I will stumble and hurt myself, but when.  :-)