🚀 go-pugleaf

 
 Daniel- Sure there's a way. It's slow and evil (at least in this 
incarnation), but it makes a lot more sense for floats...
 
 #include <math.h>
 #include <limits.h>
 
 int bad_mult(int num1, int num2)
 {
      return (log(abs(num1)) * log(abs(num2)) > log(INT_MAX)) ? 1 : 0;
 }
 
 ... now, this'll give one false negative (if the two numbers multiply to 
produce INT_MIN on a 2's complement machine or something where INT_MIN isn't 
real close in magnitude to INT_MAX), but that could be taken care of by 
slight additional code to check signs and compare against log(abs(INT_MIN)) 
if necessary.
 
 On the other hand, this is really going to slow down simple integer 
multiplies. ;)