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Article #41874Re: Calendar Formula needed
From: eer36024
Date: Tue, 13 Mar 1990 10:39
Date: Tue, 13 Mar 1990 10:39
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This may be more than what you need. This converts a year, month, and day to a "Julian Day" number. A Julian Day number MOD 7 = 0=Monday to 6=Sunday. ALL '/'s = DIV, i.e. A/B = A DIV B = TRUNC(A/B) JD = 367*Y - 7*(Y+(M+9)/12)/4 - 3*((Y+(M-9)/7)/100+1)/4 + 275*M/9+D+1721029
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arc1-ca.pugleaf.net!utzoo!utgpu!jarvis.csri.toronto.edu!cs.utexas.edu!swrinde!zaphod.mps.ohio-state.edu!brutus.cs.uiuc.edu!ux1.cso.uiuc.edu!ux1.cso.uiuc.edu!uxa.cso.uiuc.edu!eer36024References:
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Path: arc1-ca.pugleaf.net!utzoo!utgpu!jarvis.csri.toronto.edu!cs.utexas.edu!swrinde!zaphod.mps.ohio-state.edu!brutus.cs.uiuc.edu!ux1.cso.uiuc.edu!ux1.cso.uiuc.edu!uxa.cso.uiuc.edu!eer36024 From: eer36024@uxa.cso.uiuc.edu Newsgroups: comp.sys.atari.st Subject: Re: Calendar Formula needed Message-ID: <46300089@uxa.cso.uiuc.edu> Date: 13 Mar 90 10:39:39 GMT References: <53715@bu.edu.bu.edu> Lines: 7 Nf-ID: #R:bu.edu.bu.edu:53715:uxa.cso.uiuc.edu:46300089:000:281 Nf-From: uxa.cso.uiuc.edu!eer36024 Mar 12 18:20:00 1990