🚀 go-pugleaf

I know from my days of assembly programming that whenever 8086 instructions  
like OUT DX,AX were used the CPU was using the I/O bus.  On the other hand  
when instructions like MOV AX,[BX] were used the CPU was not using the I/O  
bus.  In Intel chips I/O addresses are different from memory addresses.  In  
the Motorola chips I/O devices are mapped to system memory, so in order to  
write to an I/O device the CPU simply has to write to the memory address for  
that device.

Now, I remember that in the Intel hardware there was a pin from the CPU that  
indicated that the address in the address bus was for an I/O device or for  
normal system memory.

The I/O bus in PCs (i.e. ISA) has an upper limit of 8MHz.  So they invented  
VESA local bus.  Does any one know how it works?  I think my confusion is that  
I don't know how it is accessed from assembly language?  Do you use IN/OUT or  
MOV instructions?  How does the hardware detect that VESA local bus is being  
accessed instead of system memory or ISA bus?
  
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Ricardo J. Parada