🚀 go-pugleaf

Hi!

  Just a question about hard disk transfer rates. I recently purchased a 
SCSI drive, the ST-02 (no flames please) and ST-157N. Running with the 
zero wait jumper enabled, with a 1:1 interleave I am getting 500K of
transfer rate, but running at 2:1 I am getting 350K or so. I thought 1:1 is
twice as fast as 2:1, since the disk must rotate twice to read all the sectors.
Anyone know what is going on there?

  Also, how does one get the theoretical maximum transfer rate for any
one encoding scheme (RLL/MFM/ESDI)? Doesn't the transfer rate be affected
by the number of read/write heads you have on your drive? I though the sequence
on sequential read/write on a hard disk is:

  (sector 0) head 0 1 2 3 .. (sector 1) head 0 1 2 3 .. (sector 2) head 0 1 ..

It seems this way when I format a disk. So the more heads you have, the higher
your transfer rate, since switching from head to head doesn't take any time?!
Or is it the other way:

  (head 0) sector 0 1 2 3 4 ... 17 (head 1) sector 0 1 2 3 ....

which provides a constant rate regardless of number of heads?

Also, I though Winchester drives spin at a rate of 3000 revolution per second,
as opposed to 300 rps on floppy drives. Assuming heads don't matter, the 
transfer rate formula on a 1:1 intereave is:

   3000 * SECTOR/TRACK * SECTOR SIZE 

which will give me a HUGE number. Lets assume RLL, 26 sectors/track and 512 
bytes/sector:

   3000 * 26 * 512 = 39,000 Kbytes 

which is over 39 Megabytes/second, and is about 500 times greater then 
7.5Mbits/second!! What is going on here??!

  I will appreciate if anyone can answer my question. Sorry if they seem
naive, but I just can not figure it out..

Thanks in advance,
Kwong