Re: Partitioning squares into unequal squares

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Article #1771

#1771

From: Andre Marien
Date: Thu, 30 May 1991 14:53

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The prolog system of A. Colmerauer, Prolog III, uses this as a showcase:
fill some rectangle with some (!=) squares
and comes up with only two solutions. The first is for a 33 /32 rectangle:

	9	10	14
	       1
	8	7	4
	15		18

I don't have the other one handy.

Andre' Marien

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From: bimandre@icarus.cs.kuleuven.ac.be (Andre Marien)
Newsgroups: comp.theory
Subject: Re: Partitioning squares into unequal squares
Message-ID: <3637@n-kulcs.cs.kuleuven.ac.be>
Date: 30 May 91 14:53:59 GMT
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