🚀 go-pugleaf

Christopher R Volpe <volpe@ash.crd.ge.com> writes:

>comp.std.c answer: The compiler is allowed to know the semantics of
>printf, and should know that the printf function will not modify
>flag_pt, despite the fact that other user-defined functions could.

No, the compiler can't assume anything about printf(), as the user
could have stupidly defined his own function of the same name,
overriding the expected behaviour of the version in libc.

In some of my Mach programming, I've done just that.  [Well, with
different functions, where the normal version had problems, but
still...]

Never expect a compiler to be smart, but always be prepared for it to
outsmart you.

--PC
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