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Hi,
Borg (vladimip@iceonline.com*) wrote:
: How do I display variable addresses in hex rather than in decimal?
: An example:

:   double var;
:   cout << "var value is " << var << " and its address is ";
:   cout << unsigned (&var) << endl;

I'm not sure whether it is standard conforming to do a conversion from
some pointer to an 'unsigned' (IMO it should not) but given that it
works, you can use the 'hex' manipulator, i.e.

    cout << hex << unsigned (&var) << endl;

However, the correct way to print a pointer is like this:

    cout << &var << endl;

: My (platform/OS independent) books insist on using:

: cout << &var << endl; (without "unsigned" and without 
: round brackets!) I am using gcc/g++ 2.7.2 on Linux-i586.

And, guess what, they are correct! Every pointer is convertible to
'void const *' and there is an inserter for exactly this type which
prints the address in an implementation defined way, normally in hex.
--
<mailto:dietmar.kuehl@uni-konstanz.de>
<http://www.informatik.uni-konstanz.de/~kuehl/>
I am a realistic optimist - that's why I appear to be slightly pessimistic

In article <56m5ch$noi@news.iceonline.com>, Borg <vladimip@iceonline.com*> writes:
:How do I display variable addresses in hex rather than in decimal?
:An example:
:
:  double var;
:  cout << "var value is " << var << " and its address is ";
:  cout << unsigned (&var) << endl;

Try -
   cout << (void*)&var << endl;


Rohan
-- 
Rohan Lenard - rjl@wr.com.au rjl@ot.com.au rjl@triode.net.au
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Hi,

Borg <vladimip@iceonline.com*> writes:

> 
> Hi,
> 
> A quick (dumb?) question:
> 
> How do I display variable addresses in hex rather than in decimal?
> An example:
> 
>   double var;
>   cout << "var value is " << var << " and its address is ";
>   cout << unsigned (&var) << endl;
> 
> A sample output:
> 
> [vlad@borg pointers]$ address
> var value is 6 and its address is 3221223436.
> 
> My (platform/OS independent) books insist on using:
> 
> cout << &var << endl; (without "unsigned" and without 
> round brackets!) I am using gcc/g++ 2.7.2 on Linux-i586.
> 
> Please reply in newsgroups.

i don't know is this bug or not, but in order to
get address printed, you have to explicitely cast it to
(void*).

cheers

OK

Borg wrote:
> 
> Hi,
> 
> A quick (dumb?) question:
> 
> How do I display variable addresses in hex rather than in decimal?

To output the address, cast the pointer to void* (because some other pointer
types, such as char*, get special treatment). To get the output in hex,
use the hex inserter:
	ostr << hex << (void const*)&variable;

-- 

Ronald Otto Valentin Fischer
business: ronald.fischer@uebemc.siemens.de
private:  ronald.fischer@acm.org
http://ourworld.compuserve.com/homepages/ronald_fischer