🚀 go-pugleaf

In article <1992Jul31.035445.24776@latcs1.lat.oz.au> wongm@latcs1.lat.oz.au (/home/pgrds/wongm) writes:
>Hello,
>  I have a simple question to ask, ie when using du command, how can
>  can we have the listing sorted with the file size as sort key.
>
>  I tried : du | +0 -1 but this will not give correct result,
>  since if we have :
>
>  file    size
>  ----    ----
>  A       10
>  B       2
>  C       3
>
>  The outout from the pipeline is "
>
>  10	./A
>  2		./B
>  3		./C
>
>  How can we do it correctly, do we have to pipe the field 0 from
>  du to bc or some similar command to do that ?

A simple solution is to do something like this

du | sort -r +0 -1 | awk '{ printf("%-60s %s\n", $2, $1); }'

the sort -r is to reverse the sort according to file size.  The -60s in the
printf statement assumes that pathnames will not exceed 60 characters length.
You need to modify this value of 60 to suit your purpose.  The output is
formatted nicely with the above values though.

Patrick Lobo