🚀 go-pugleaf

Patrick Lobo writes
> In article <1992Jul31.035445.24776@latcs1.lat.oz.au> wongm@latcs1.lat.oz.au  
(/home/pgrds/wongm) writes:
> >Hello,
> >  I have a simple question to ask, ie when using du command, how can
> >  can we have the listing sorted with the file size as sort key.
> >
> >  I tried : du | +0 -1 but this will not give correct result,
> >  since if we have :
> >
> >  file    size
> >  ----    ----
> >  A       10
> >  B       2
> >  C       3
> >
> >  The outout from the pipeline is "
> >
> >  10	./A
> >  2		./B
> >  3		./C
> >
> >  How can we do it correctly, do we have to pipe the field 0 from
> >  du to bc or some similar command to do that ?
> 
> A simple solution is to do something like this
> 
> du | sort -r +0 -1 | awk '{ printf("%-60s %s\n", $2, $1); }'
> 
> the sort -r is to reverse the sort according to file size.  The -60s in the
> printf statement assumes that pathnames will not exceed 60 characters length.
> You need to modify this value of 60 to suit your purpose.  The output is
> formatted nicely with the above values though.
> 
> Patrick Lobo


A even more simple solution is:
ls -l | sort -nr +3 

-- peer