Passing variables in gawk.

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Article #4148

#4148

From: Srihari Kotcherlakota
Date: Tue, 21 Apr 1992 05:41

26 lines
1300 bytes

Script gawk.bug:

#!/bin/csh
nawk \
'\
END { print "var1 = ", var1 }' \
/dev/null var1="nawk works"
awk \
'\
END { print "var1 = ", var1 }' \
/dev/null var1="awk works"
gawk \
'\
END { print "var1 = ", var1 }' \
/dev/null var1="gawk works"

What happens when I run the above test:

gawk.bug
var1 =  nawk works
var1 =  awk works  # I had to hit Ctrl-D to force this message
gawk: var1=gawk works: No such file or directory

Question: Is this a known bug in gawk?

Please reply to hari@fai.fmiapd.com

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Message-ID: <1992Apr21.054153.22451@leland.Stanford.EDU>

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From: harik@leland.stanford.edu (Srihari Kotcherlakota)
Newsgroups: comp.unix.shell,gnu.utils.bug
Subject: Passing variables in gawk.
Message-ID: <1992Apr21.054153.22451@leland.Stanford.EDU>
Date: 21 Apr 92 05:41:53 GMT
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