🚀 go-pugleaf

douglas jackson (jacksond@alain.cs.colostate.edu) wrote:
[ this statement ]
: cout <<Stck1.Top_STK()<<Stck1.Pop_STK()<<endl;
[ and these statements ]
: cout <<Stck1.Top_STK();
: cout <<Stck1.Pop_STK()<<endl;
[ give different results ]
: Is there some sort of order of
: operations in a cout statement with classes?  

The technical term here is "sequence point" - the first statement
is a single expression, and it contains expressions with side-effects
(the "Top_STK" and "Pop_STK" calls).  Consequently, the Top and Pop
are evaluated in some undefined order before operator<< is invoked
to write to cout.

Your latter structure is more correct, or you can use temporary
variables to make the order of computation explicit.

    Ken Shrum