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Article #148STUNTWOMAN PROBLEM
From: bugnib
Date: Sun, 17 Feb 2008 22:36
Date: Sun, 17 Feb 2008 22:36
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1779 bytes
1779 bytes
I saw that there were some questions on the stuntwomen/helicopter problem...this is how i solved it: First, use the equation (change in y)=(Voy)(t^2) - (g/2) t^2 so we have, 33m=(12m/s) t - 9.81/2 t^2 Next, set this equation equal to zero... 4.905t^2 - 12t + 33=0 Plug this into the quadratic equation and solve for "t"... (12 +/- square root( (-12)^2 - 4 (4.905) (3) )) / 2 (4.905) When you solve this you get t=4.09s Note: you also get a negative t but as we know, time cannot be negative! Now take 4.09s x 15 m/s = 61.4 m Thus, the stuntwoman should place her mats 61.4 m towards the south.
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X-Google-Thread: f4cf3,dd61d5af15af5315,start X-Google-Attributes: gidf4cf3,public,usenet X-Google-Language: ENGLISH,ASCII-7-bit Path: arc1-ca.pugleaf.net!g2news1.google.com!postnews.google.com!s19g2000prg.googlegroups.com!not-for-mail From: bugnib@unlv.nevada.edu Newsgroups: cu.physics.ugrads Subject: STUNTWOMAN PROBLEM Date: Sun, 17 Feb 2008 14:36:51 -0800 (PST) Organization: http://groups.google.com Lines: 24 Message-ID: <b950756b-316a-455e-81e7-5293d12f7db9@s19g2000prg.googlegroups.com> NNTP-Posting-Host: 68.224.155.82 Mime-Version: 1.0 Content-Type: text/plain; charset=ISO-8859-1 Content-Transfer-Encoding: 7bit X-Trace: posting.google.com 1203287812 10674 127.0.0.1 (17 Feb 2008 22:36:52 GMT) X-Complaints-To: groups-abuse@google.com NNTP-Posting-Date: Sun, 17 Feb 2008 22:36:52 +0000 (UTC) Complaints-To: groups-abuse@google.com Injection-Info: s19g2000prg.googlegroups.com; posting-host=68.224.155.82; posting-account=txEpsAoAAABdYLzHrVujht7G_M6GrQoJ User-Agent: G2/1.0 X-HTTP-UserAgent: Mozilla/5.0 (Macintosh; U; Intel Mac OS X; en) AppleWebKit/523.12.2 (KHTML, like Gecko) Version/3.0.4 Safari/523.12.2,gzip(gfe),gzip(gfe)