🚀 go-pugleaf

Ryan A. Rowe wrote in message <3626B01E.CA8C024C@hotmail.com>...
>Hi guys,
>
>I could really use some help with a couple of questions for my physics
>homework. Here they are:
>
>A speedy tortoise can run at 10.0 cm/s and a hare can run 20 times as
>fast. In a race they start at the same time, but the hare stops to rest
>for 2.0 minutes, and so the tortoise wins the race by 20 cm.
>
>a) How long does the race take?
>b) What is the length of the race?

    Assume that the tortoise runs for 2 minutes, there are 60 seconds in a
minute, and since the tortoise can only travel 10 cm a second that the total
distance the tortoise can travel is 600 cm, or 6 meters in a minute, which
would be twelve in two.  If the Hare looks up at the very last minute, and
the tortoise wins by a nose.  The distance the Hare can travel in two
minutes is 20 times farther than the tortoise, which would be 240 meters in
two minutes.  Since, the tortoise has already traveled 12 meters in two
minutes, and the Hare could cover the distance in 1/20th of the time, if I
take the time that the tortoise would take to reach the distance by the
recipicol of 1/20 and add one which is 1.05 and subtract .001 from that,
than multiply it by the distance that the tortiose has traveled then I have
12 Meters, and 60 cm. where the Hare lost by a nose.


>
>I can't figure out what equation to use to solve this problem or how to
>even begin figuring it out, it's just so confusing! Can someone help me
>please?
>
>Here is the second question I am having trouble with:
>
>A particle moves along x-axis according to the equation
>x = 2.0 + 3d - 1.0t (the last t is squared), where x is in meters and t
>in seconds. At t= 3.0 seconds, find:
>
>a) The position of the particle
>b) Its velocity
>c) Its acceleration
>
    I cannot tell you what the constant stands for, but it should be in the
Physics Book you bought for the class.

>First of all, what is the variable d??? I can't even figure that out. I
>do know that I have to use the rules of differential calculus but even
>when I do that, I come out with some weird answer, like -3 m/s for the
>velocity. When I graph the position-time graph, I get a slope of -2 m/s
>for the velocity.
>
>Please send any advice to calidream@hotmail.com
>Much appreciated and thanks in advance!
>
>Ryan A. Rowe
>calidream@hotmail.com
>
>