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Article #63

Re: In terms of v0, theta, and g

#63
From: John Dredla
Date: Tue, 19 Feb 2008 04:39
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I started by converting 385 ft to meters.

385(30.48 cm/ft)((1m/100cm) = 117.3 m


find Vi:
Vi = sqare root (Rg/sin2theta) = sqare root of (117)(9.8)/sin54
degrees) = 37.7 m/s

Find Height
H = Vi^2Sin^2theta/2g
    =[ (37.7 m/s)(0.4539)^2]/2(9.8)  = 14.9m


I wish there were a way to write math better here, subscripts and
greek letters.  

hope this helps,



On Mon, 18 Feb 2008 12:25:42 -0800 (PST), TEL
<ted_e_llama@hotmail.com> wrote:

>
>
>Well i was wondering on a problem like 3.19, where it give an angle
>and an x value and you are asked to solve for Vinitial.  Everything I
>came up w/ was incorrect.  I am wondering if anyone could point me in
>the right direction for solving.
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From: John Dredla <Jdredla@hotmail.com>
Newsgroups: cu.physics.ugrads
Subject: Re: In terms of v0, theta, and g
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Date: Mon, 18 Feb 2008 20:39:18 -0800