Re: Ch6 HW

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Article #80

#80

From: TEL
Date: Thu, 06 Mar 2008 06:14

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On Mar 5, 4:45 pm, John Dredla <Jolt...@hotmail.com> wrote:
> 6.23 ends up with a quadratic equation to solve for the radius. this
> will point you in the right direction.  My my original masses are
> 3.60m apart, so the mass that would go in the middle is radius 3.60-r
>
> ~J
>
> On Wed, 5 Mar 2008 02:32:55 -0800 (PST), TEL <ted_e_ll...@hotmail.com>
> wrote:
>
> >Im currently stuck on problem 6.22 and 6.23 from the homework.  Im
> >guessing I misunderstood what Dr. Pravica said about multiple objects
> >effects on one another.  Any help in the right direction would be
> >appreciated.

Maybe you can tell me what im missing.  I have it set up that the
force between m and 3m is (G*m*3m)/1.8^2 (1.8 was the distance i was
given) and this force needs to equal the negative of the force of the
3rd mass, -(G*m1*m3)/r^2.  I set these 2 equal to each other and tried
to solve which gave me a distance of 1.04m.  Can you tell me where I
am going wrong?

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From: TEL <ted_e_llama@hotmail.com>
Newsgroups: cu.physics.ugrads
Subject: Re: Ch6 HW
Date: Wed, 5 Mar 2008 22:14:29 -0800 (PST)
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