Re: More CH6 ?

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Article #84

#84

From: TEL
Date: Sat, 08 Mar 2008 10:35

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On Mar 7, 6:05 am, John Dredla <Jolt...@hotmail.com> wrote:
> find the gravity there  grav = 2h/t^2
>
> Circumference =2piR, find R    R=C/2pi
>
> mass = (grav)R^2)/G       G is the gravitational constant
>
> mass of planet / mass of earth
>
> --------------------------------------
>
> Find the distance from the pole to the block
> Hypontenuse^2 - 1/2 length2, then square root
>
>   sq rt  H^2 - L1  = L2
>
> Tension in lower called Tl
> Tension in upper called Tu
>
> Tl = Tu - (Hype/L1)mg
>
> second part of problem  solve for V
>
> a=v^2/R   F=ma
>
> substitute a into second equation
>
> F=mV^2/R
>
> set it equal to the tensions, don't forget to add given upper tension
> with found lower tension
>
> Hope this helps
>
> On Thu, 6 Mar 2008 23:39:39 -0800 (PST), TEL <ted_e_ll...@hotmail.com>
> wrote:
>
> >If anyone could help w/ 6.27 and the EC 6.57 it would be greatly
> >appreciated (before 10:00am :D).  Again, not sure what im missing.
>
> >Thanks

Could you go through your logic on these 2, how you derived them and
such?

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From: TEL <ted_e_llama@hotmail.com>
Newsgroups: cu.physics.ugrads
Subject: Re: More CH6 ?
Date: Sat, 8 Mar 2008 02:35:14 -0800 (PST)
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