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Article #54582Re: What is Celcius in Fahrenheight?
From: Rusty Haddock
Date: Thu, 16 Jul 1992 00:19
Date: Thu, 16 Jul 1992 00:19
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1695 bytes
How 'bout this one:
F = ((C + 40) * 9/5) - 40
The inverse then becomes:
C = ((F + 40) * 5/9) - 40
You always add 40 to the given temperature, multiply by the appropriate
scaling factor, and subtract 40. The formula everyone has been giving is
equivalent so it's just a different way to write the equation and, for me,
easier to remember. Remembering the scale factor (5/9 or 9/5) is a matter
of dimensional analysis and/or remembering 9-degs F to 5-degs C. Fahrenheit
is a "finer" scale.
(C+40)*9/5 - 40
C*9/5 + 40*9/5 - 40
C*1.8 + 8*9 - 40
C*1.8 + 72 - 40
C*1.8 + 32
-Rusty-
--
Rusty Haddock / Computer Science Dept DOMAIN: rusty@mimsy.cs.umd.edu
University of Maryland PATH: {uunet,rutgers}!mimsy!rusty
If someone points a quad-vectored, hyper-thermic, cosmo blaster
at you it's a safe bet that you're about to become toast.
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X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: 101049,3976bc13e6a45811 X-Google-Attributes: gid101049,public X-Google-ArrivalTime: 1992-07-15 12:44:00 PST Path: arc1-ca.pugleaf.net!sparky!uunet!newsgate.watson.ibm.com!news.ans.net!europa.asd.contel.com!darwin.sura.net!dtix!mimsy!mimsy.cs.umd.edu!rusty From: rusty@krishna.cs.umd.edu (Rusty Haddock) Newsgroups: dc.general Subject: Re: What is Celcius in Fahrenheight? Message-ID: <RUSTY.92Jul15201901@krishna.cs.umd.edu> Date: 16 Jul 92 00:19:01 GMT References: <733@dcprinc.UUCP> <22351@oasys.dt.navy.mil> Sender: news@mimsy.umd.edu Followup-To: dc.general Distribution: dc Organization: U of Maryland, Dept. of Computer Science, Coll. Pk., MD 20742 Lines: 28 In-reply-to: mcostell@oasys.dt.navy.mil's message of 15 Jul 92 17:53:27 GMT