Re: angewandte Vektorenrechnung

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#313

From: Anselm Proschniewski
Date: Thu, 06 Apr 2000 00:00

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Michael Prechtel wrote:
> 
> Hallo!
> 
> Kann mir jemand mit folgender Aufgabe helfen! Sie ist leider in Englisch!
> 
> At time t seconds, the force F newtons acting on a particle P is given by
> "F"=(t+3)"i"-2t"j"
> where "i" and "j" are perpendicular horizontal unit vectors. P has mass 2
> kg, and its velocity
> ,when t=0, is -1/2("i"+3"j") ms^-1.
> 
> find:
> a) the velocity of P at time t seconds

mit Newtons Axiom "F = m * a" folgt:
x" = F/m = ((t+3)*i -2*t*j)/2

integrieren nach der Zeit t: 

x' = (t�/4 + 3/2t + K1)*i + (-t�/2 + K2)*j
x'(t=0) = K1*i + K2*j 
K1 = -1/2, K2 = -3/2

x'(t) = (t�/4 + 3/2*t -1/2)*i + (-t�/2 -3/2)*j

Ist das so schwer ? 

Anselm aus Stuttgart

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From: Anselm Proschniewski <proschniewski@str.daimler-benz.com>
Subject: Re: angewandte Vektorenrechnung
Date: 2000/04/06
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