🚀 go-pugleaf

*puntero_loco wrote:

>  el programa sin chorraditas quedar�a:
>
> void send(int* to, int* from, int count)
> {
>         int n = (count+7)/8;
>         switch(count%8) {
>         case 0: do {
>                 *to++ = *from++;
>                 } while (--n>0);
>        case 7:         *to++ = *from++;
>        case 6:         *to++ = *from++;
>        case 5:         *to++ = *from++;
>        case 4:         *to++ = *from++;
>        case 3:         *to++ = *from++;
>        case 2:         *to++ = *from++;
>        case 1:         *to++ = *from++;
>         }
> }

Discrepo: empleando una sintaxis m�s ortodoxa, su
equivalente ser�a esto:

void send(int* to, int* from, int count)
{
        int n = (count+7)/8;
        do {
        switch(count%8) {
        case 0:  do {
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
             } while (--n>0);
             break;
        case 1:  do {
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
             } while (--n>0);
             break;
         case 2: do {
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
             } while (--n>0);
             break;
         case 3: do {
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
             } while (--n>0);
             break;
         case 4: do {
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
             } while (--n>0);
             break;
         case 5: do {
                  *to++ = *from++;
                  *to++ = *from++;
                  *to++ = *from++;
             } while (--n>0);
             break;
         case 6: do {
                  *to++ = *from++;
                  *to++ = *from++;
             } while (--n>0);
             break;
         case 7: do {
                  *to++ = *from++;
             } while (--n>0);
         }
 }

... que SI es inteligible.