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Article #9152Re: bash: ambito de variables con while
From: NotFound
Date: Thu, 29 Aug 2002 17:06
Date: Thu, 29 Aug 2002 17:06
17 lines
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1284 bytes
jG-PPz escribió: > Por qué el ambito de una variable en bash dentro de un while se > acaba al salir de éste? > > ---SCRIPT: prueba.sh --- > #!/bin/bash > while read variable > do > echo "valor: $variable" > done No es que la variable salga de ambito, es que el ultimo read, el que devuelve false y termina el while, la deja en blanco. Salu2
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X-Google-Language: SPANISH,ASCII X-Google-Thread: f86c8,b26f7a7eb5428370 X-Google-Attributes: gidf86c8,public X-Google-ArrivalTime: 2002-08-29 11:01:55 PST Path: arc1-ca.pugleaf.net!archiver1.google.com!news1.google.com!newsfeed.stanford.edu!skynet.be!skynet.be!newsfeed.icl.net!newsfeed.fjserv.net!lnewspeer00.lnd.ops.eu.uu.net!emea.uu.net!cesio.mundo-r.com!not-for-mail From: NotFound <correo@tengo.no> Newsgroups: es.comp.os.linux.programacion Subject: Re: bash: ambito de variables con while Date: Thu, 29 Aug 2002 19:06:07 +0200 Organization: Another Netscape Collabra Server User Lines: 17 Message-ID: <3D6E547F.9C3B3CC3@tengo.no> References: <lnclka.5q3.ln@192.168.0.102> NNTP-Posting-Host: cm65010.red.mundo-r.com Mime-Version: 1.0 Content-Type: text/plain; charset=iso-8859-1 Content-Transfer-Encoding: quoted-printable X-Mailer: Mozilla 4.77 [es] (X11; U; Linux 2.4.4-4GB i686) X-Accept-Language: en