Re: 剰余について

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Article #225

#225

From: MAEDA Atusi
Date: Mon, 16 Mar 1998 00:00

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maeda@src.ricoh.co.jp (Kaoru MAEDA) writes:

> Perl5.004で規定?された(regulateされた)ようです。
> 
> man perlopより:
> |     Binary "%" computes the modulus of two numbers.  Given
> |     integer operands $a and $b: If $b is positive, then $a % $b
> |     is $a minus the largest multiple of $b that is not greater
> |     than $a.  If $b is negative, then $a % $b is $a minus the
> |     smallest multiple of $b that is not less than $a (i.e. the
> |     result will be less than or equal to zero).

なるほど。floorの余りを採用したんですね。佐藤さんが最初におっしゃった
mathematically correctな剰余ですね。

たしかに、Perl 5.004ではそういう値を返しますね。Perl 5.003だと、除数
($b)が負の時はむちゃくちゃ^^;。マニュアル見ても

｜       Binary "%" computes the modulus of the two numbers.

と書いてあるだけだし。

				前田敦司

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From: MAEDA Atusi <maeda@is.uec.ac.jp>
Subject: Re: 剰余について
Date: 1998/03/16
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