Article View: fj.sci.math
Article #14210Re: probability question (EASY!)
From: Yoshinori TANABE
Date: Mon, 22 Feb 1993 12:22
Date: Mon, 22 Feb 1993 12:22
35 lines
2358 bytes
2358 bytes
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Message-ID: <TANUMA.93Feb19025303@mathc.math.titech.ac.jp>$@$G(J
$@ED>B(J( tanuma@mathc.math.titech.ac.jp )$@$5$s(J:
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1/3.5 = 2/7 $@$8$c$J$$!)(J
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Message-ID: <TAKEMURA.93Feb22092140@aji.tamaru.kuee.kyoto-u.ac.jp>$@$G(J
$@C]B<(J( takemura@tamaru.kuee.kyoto-u.ac.jp )$@$5$s(J:
$@C]B<(J> p(n)=p(n-1)/6 + p(n-2)/6 + p(n-3)/6
$@C]B<(J> + p(n-4)/6 + p(n-5)/6 + p(n-6)/6
$@$h$j!$(Jp(n-6)+2p(n-5)+3p(n-4)+4p(n-3)+5p(n-2)+6p(n-1) $@$O(Jn$@$K$h$i$J$$(J
$@Dj?t$G$"$k$3(J$@$H$,H=$j$^$9!%$3$NDj?t$N(J1/21 ( = 1/(1+2+3+4+5+6) )$@$r(J
k$@$HCV$/$H!$(J
p(n)-k = 1/42 * { 5p(n-6)+3p(n-5)+p(n-4)-p(n-3)-3p(n-2)-5p(n-1) }
= 1/42 * { 5*(p(n-6)-k) + 3*(p(n-5)-k) + 1*(p(n-4)-k)
- 1*(p(n-3)-k) - 3*(p(n-2)-k) - 5*(p(n-1)-k) }
$@$G$9!%$D$^$j!$(J
| p(n)-k | <= (5+3+1+1+3+5)/42 * max{ |p(n-i)-k| : i=1,..,6}
$@$H$J$j!$(Jp(n)$@$O(Jk$@$K<}B+$7$^$9!%$3$NLdBj$N>l9g$O!$(J
k = (p(-5)+2*p(-4)+3*p(-3)+4*p(-2)+5*p(-1)+6*p(0))/21 = 2/7
$@$G$7$?!%(J
--
| $@EDJU(J $@NIB'(J $@!w(J $@IY;NDL(J $@@n:j9)>l(J
| E-mail: tanabe@ai.cs.fujitsu.co.jp
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X-Google-Language: Japanese,JIS X-Google-Thread: f4956,fc23536e46178b6f X-Google-Attributes: gidf4956,public X-Google-ArrivalTime: 1993-02-22 04:22:15 PST Path: arc1-ca.pugleaf.net!sparky!uunet!stanford.edu!sun-barr!sh.wide!fgw!fdm!csnews!virgo!tanabe From: tanabe@ai.cs.Fujitsu.Co.JP (Yoshinori TANABE) Newsgroups: fj.sci.math Subject: Re: probability question (EASY!) Message-ID: <TANABE.93Feb22212215@Polaris.ai.cs.Fujitsu.Co.JP> Date: 22 Feb 93 12:22:15 GMT References: <TANUMA.93Feb19025303@mathc.math.titech.ac.jp> <TAKEMURA.93Feb22092140@aji.tamaru.kuee.kyoto-u.ac.jp> Sender: news@ai.cs.fujitsu.co.jp Distribution: fj Organization: Fujitsu Ltd., Kawasaki Japan Lines: 35 In-reply-to: tanuma@mathc.math.titech.ac.jp's message of 19 Feb 93 02:53:03 JST