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Article #9042Re: definir la DTD d'un fichier XML avec XSLT?
From: Thomas Broyer
Date: Mon, 04 Jun 2001 14:10
Date: Mon, 04 Jun 2001 14:10
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1433 bytes
In <3B1B90C2.C00F9EA7@imag.fr>, tahia wrote: > je veux tansformer un fichier XML1(sa DTD est DTD1) en un autre XML2(sa > DTD est DTD2). Je transforme XML1 a XML2 en utilisant un fichier XSLT. > Comment ajouter dans le fichier XML2 la ligne (par exemple): > <!DOCTYPE blabla SYSTEM "c:\DTD\DTD2.dtd"> <xsl:output doctype-system="file:///c:/DTD/DTD2.dtd" /> cf. spec. XSLT <http://www.w3.org/TR/xslt> , 16 Output NOTE: "c:\DTD\DTD2.dtd" n'est pas un URL. Tom.
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X-Google-Language: FRENCH,ASCII-7-bit X-Google-Thread: 114f60,7f67ed8d3f79cee2 X-Google-Attributes: gid114f60,public X-Google-ArrivalTime: 2001-06-04 07:10:04 PST Path: arc1-ca.pugleaf.net!archiver1.google.com!newsfeed.google.com!newsfeed.stanford.edu!news-spur1.maxwell.syr.edu!news.maxwell.syr.edu!opentransit.net!proxad.net!feeder2-1.proxad.net!nnrp6.proxad.net.POSTED!not-for-mail Message-ID: <1448559.UtdWV9SEqC@ltgt.net> From: Thomas Broyer <ptittom+news@free.fr> Subject: Re: definir la DTD d'un fichier XML avec XSLT? Newsgroups: fr.comp.text.xml References: <3B1B90C2.C00F9EA7@imag.fr> Lines: 13 Organization: </> MIME-Version: 1.0 Content-Type: text/plain; charset=us-ascii Content-Transfer-Encoding: 7Bit Date: Mon, 04 Jun 2001 14:10:02 GMT NNTP-Posting-Host: 193.252.183.203 X-Complaints-To: abuse@proxad.net X-Trace: nnrp6.proxad.net 991663802 193.252.183.203 (Mon, 04 Jun 2001 16:10:02 CEST) NNTP-Posting-Date: Mon, 04 Jun 2001 16:10:02 CEST