🚀 go-pugleaf

 > I thought that was the point of `protected' vs. `private'.  If you change
 > to private you get the error.
 > 
 > 				beshers@carcvax.brc.uconn.edu

Hi,

I believe you're getting confused by the following (which is
admittedly weird at face value):

----------------------------------------
class foo {
protected:
   int i;
};

main () {
   foo bar;
   
   bar.i = 10; // error, protected members are not
               // visible to objects of the base
               // type.
}

g++ correctly says:

----------------------------------------
In function int main ():
test.c:11: member `i' is a protected member of class `foo'
----------------------------------------

However, the following *is* correct:

----------------------------------------
class foo {
protected:
   int i;
};

class bar : public foo {

public:   
   f () {
      i = 10; // OK, since bar is a derived type
   }
};
----------------------------------------

If you look at the example I showed (from Stroustrup's article, so it
had *better* be correct ;-)), you'll see that 

----------------------------------------
X a;
a.prot
----------------------------------------

is clearly trying to get ahold of the protected member, in the same
illegal sense of my first example above.  After all, ``a is not a Y!''

Does that make any more sense?

Doug