🚀 go-pugleaf

Hi,

   G++ 1.32 incorrectly handles the scope of enumerated types
declared in struct's and classes.  Here's an example:

----------------------------------------
int FOO = 10;

struct foo {
   enum bar { FOO, BAR };   
};

main ( ) {
   int i = FOO;
   printf ( "i = %d\n", i); // this should print out 10
}
----------------------------------------

g++ doesn't compile the code above, complaining that:

----------------------------------------
foo.c:4: `FOO' redeclared as different kind of symbol
foo.c:1: previous declaration of `FOO'
foo.c:4: warning: `FOO' was declared `extern' and later `static'
----------------------------------------

However, according to Lippman and Moo:

``In C++, enumerations are local to the class [ or struct ] in which
they are declared.''  ( page 131, 1988 USENIX C++ Conference
Proceedings ).

Therefore, the only correct way to reference enum bar's FOO is via
the visibility operator, i.e.:

int i = foo::FOO // sets i to 0, in this case.

g++ seems to be erroneously using the C visibility rules in this case.

Doug