implicit member-wise assignment

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2 total messages Started by Gary Lipton Thu, 09 Apr 1992 05:46

#45

Author: Gary Lipton
Date: Thu, 09 Apr 1992 05:46

21 lines
884 bytes

I am just learning C++.  My references tell me that "=" is
implicitly defined as member-wise assignment between operands
of a given class.

That is, if I have a class "Foo", then the code

   Foo foo1, foo2;

   foo1 = foo2;

is legal, and will copy the members of foo1 into foo2, without
an explicit declaration of "=".

But I find that using g++, I would need the statement

  Foo operator=(Foo);

in my Class declaration for this code to compile.

Is there a way to get g++ to provide implicit assignment?  Or
am I on the wrong track entirely?

Re: implicit member-wise assignment

#69

Author: Don &
Date: Fri, 17 Apr 1992 06:44

50 lines
1664 bytes

>>>>> On 9 Apr 92 05:46:54 GMT, glipton@ajax.intel.com (Gary Lipton) said:

Gary> That is, if I have a class "Foo", then the code

Gary>    Foo foo1, foo2;

Gary>    foo1 = foo2;

Gary> is legal, and will copy the members of foo1 into foo2, without
Gary> an explicit declaration of "=".

Gary> But I find that using g++, I would need the statement

Gary>   Foo operator=(Foo);

Gary> in my Class declaration for this code to compile.

That's funny.  I'm using gcc-2.1 on a Sparc running SunOS4.1.1
and implicit assignment works fine for me.  The code appended
to this message comiles fine with the command "g++ assig.cc"

By the way, the usual assingment operator is

  Foo& operator=(const Foo&);

Don Bashford
bashford@scripps.edu

--------------------------assig.cc------------------------------
class Pub {
public:
  int x, y;
  Pub(int xc, int yc) {x = xc; y=yc;}
};

class Priv {
private:
  int x, y;
public:
  Priv(int xc, int yc) {x = xc; y=yc;}
};

main() {
  Pub pub1(2,3);
  Pub pub2(4,5);
  pub2 = pub1;
  Priv priv1(5,6);
  Priv priv2(7,8);
  priv2 = priv1;
}

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