implicit member-wise assignment

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1 total messages Started by John D. Sutter Fri, 10 Apr 1992 04:05

#48

Author: John D. Sutter
Date: Fri, 10 Apr 1992 04:05

27 lines
1032 bytes

 [ posted for a friend -- jds ]

I am just learning C++.  My references tell me that "=" is
implicitly defined as member-wise assignment between operands
of a given class.

That is, if I have a class "Foo", then the code

   Foo foo1, foo2;

   foo1 = foo2;

is legal, and will copy the members of foo1 into foo2, without
an explicit declaration of "=".

But I find that using g++, I would need the statement

  Foo operator=(Foo);

in my Class declaration for this code to compile.

Is there a way to get g++ to provide implicit assignment?  Or
am I on the wrong track entirely?

Please send replies to glipton@sedona.intel.com; our news access
has been shut down recently.  Thanks.

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