🚀 go-pugleaf

User Jdsmith wrote:
> 
> I am experiencing a problem with overloading the
> new operator when allocating an array of classes.
> 
> I do the following and my overloaded new operator is
> called as expected:
> 
> ptr = new ClassThatOverloadsNew;
> 
> But when I do this:
> 
> ptr = new ClassThatOverloadsNew[5];
> 
> The default new operator is called.
> 
> What needs to be done to get an overloaded new operator to be called
> when allocating an array of data types?  Does C++ even allow this
> to be done?  I have checked several C++ manuals and none explicitely
> state that this can be done (and none say that it cannot be done!).
> I assumed that the overloaded new operator would be called with the
> number of bytes (the first parameter) being set to:
> 
> sizeof(class) * arrayCount
> 
> But this is not the case.  Does anybody know how to solve this problem?
> I'm sure it is supported and is simple to do, I just have not found the
> right documentation on how to do it.  My assumptions have been wrong so
> far, so I need some help.
> 

You have to provide array new/delete operators.
For instance, the subsequent code shows how to overload the appropriate
allocation functions for a class 'A':

>>>>
#include <iostream.h>
#include <new.h>

struct A {
  void* operator new (size_t t) { 
    cout << "new\n"; 
    return :: operator new(t); 
  }
  void* operator new[] (size_t t) { 
    cout << "new[]\n"; 
    return :: operator new[](t); 
  }
  void operator delete(void* p) { 
    cout << "delete\n"; 
    :: operator delete(p); 
  }
  void operator delete[](void* p) {
    cout << "delete[]\n"; 
    :: operator delete(p); 
  }
};

int main()
{
  delete new A;
  delete[] new A[5];
  return 0;
}
<<<<

When an array of objects of type 'A' is created 'A:: operator new[](size_t)' is called.
'A:: operator delete[](size_t)' is used to release the allocated memory when the array
is destructed.

	Enno