🚀 go-pugleaf

> The compiler may still barf, since you are trying to dereference a
> NULL pointer (guarnteed to be a problem), ....

A couple of other people fell in a similar pit.  The code (expanded):

	char *foo = (char *)(((struct test *)0)->s);

does *not* dereference any pointers.  `s' is an array so it could
have been written &((struct test *)0)->s[0]), but that is unnecessary,
the (char *) is simply a cast, and perhaps the most subtle:
"((struct test *)0)->" does not dereference through zero, rather
is says that 0 is the *value* (i.e. contents) of the struct pointer.
What the expression really means is "give me the address of the s
array within a structure located at address zero", i.e. what is the
byte offset of s within the structure.  It really is static.

I wasn't kidding what I listed all of the C compilers that can handle
this correctly.

- Phil