Re: difference between x->y and *(x.y)???

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Article #42578

#42578

From: Hans Werner Strube
Date: Sat, 11 Nov 1995 00:00

26 lines
1212 bytes

Asko Seeba (asko@hapnik.ut.ee) wrote:
: If i wrote

:     case STRING: return ( id->string_id != ident.id->string_id );

: then compiler cried:

: id.cc:54: base operand of `->' is not a pointer
: id.cc:54: base operand of `->' is not a pointer

: ident is ID type.
: If i wrote

:     case STRING: return ( *( id.string_id ) != *( ident.id.string_id ) );

: then compiler ate it :). To this point i thought that it is the same... but
: now i start to think something else... but what? dunno... Can anyone explain
: it?

id->string_id is not *(id.string_id) but (*id).string_id !

--

 Hans Werner Strube          strube@physik3.gwdg.de
 Drittes Physikalisches Institut,  Univ. Goettingen
 Buergerstr. 42-44,   D-37073 Goettingen,   Germany

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From: strube@physik3.gwdg.de (Hans Werner Strube)
Subject: Re: difference between x->y and *(x.y)???
Date: 1995/11/11
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