Re: difference between x->y and *(x.y)???

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Article #42615

#42615

From: Steffen Ries
Date: Wed, 15 Nov 1995 00:00

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In article <47u2jr$ie0@kadri.ut.ee>, Asko Seeba <asko@hapnik.ut.ee> wrote:

>id.cc:54: base operand of `->' is not a pointer
>id.cc:54: base operand of `->' is not a pointer
>
>ident is ID type.
>If i wrote
>
>    case STRING: return ( *( id.string_id ) != *( ident.id.string_id ) );
>
>then compiler ate it :). To this point i thought that it is the same... but
>now i start to think something else... but what? dunno... Can anyone explain
>it?

x->y means: access member `y' of the structure `x' points to. This is
equivalent to `(*x).y'.

*(x.y) means: access the memory the member `y' of the structure `x'
points to. (This is equivalent to `*x.y')

cu, Steffen
-- 
steffen.ries@gondolin.camelot.de  | .sig intentionally left blank
steffen_ries@m4.maus.de           |

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From: str@gondolin.camelot.de (Steffen Ries)
Subject: Re: difference between x->y and *(x.y)???
Date: 1995/11/15
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