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Article #53658buliding gcc on a Sequent Symmetry without 80387
From: G.D.Pratt
Date: Thu, 26 Sep 1991 13:37
Date: Thu, 26 Sep 1991 13:37
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1248 bytes
Does anyone know how to build gcc 1.40 on a Sequent Symmetry that has Weitek FPUs not 80387? I remember with an earlier version I built with the default Sequent 386 version and had to use the "-msoft-float" flag all the time. In the file ./config/tm-seq386.h it has /* By default, target has a 80387. */ #define TARGET_DEFAULT 1 but no mention of what to do if you don't have a 80387. Is it just #define TARGET_DEFAULT 0 or perhaps it doesn't matter. BTW this is under DYNIX(R) V3.1.2 NFS #18 thanks, gerry -- gerry pratt -- workstation support -- university of keele email: gerry@seq1.keele.ac.uk * telephone : 0782 583072 "these opinions are mine, mine, Mine.....ALL MINE I TELL YOU!"
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X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: 11318c,aed7fd0fa720d86e,start X-Google-Attributes: gid11318c,public X-Google-ArrivalTime: 1991-09-27 06:01:05 PST Path: arc1-ca.pugleaf.net!gmdzi!unido!mcsun!uknet!ukc!ukc!keele!gerry From: gerry@seq1.keele.ac.uk (G.D.Pratt) Newsgroups: gnu.gcc.help Subject: buliding gcc on a Sequent Symmetry without 80387 Keywords: fpa weitek 386 387 Sequent DYNIX Message-ID: <1551@keele.keele.ac.uk> Date: 26 Sep 91 13:37:10 GMT Organization: University of Keele, England Lines: 20