Article View: gnu.utils.bug
Article #135Passing variables to gawk doesn't work?
From: Srihari Kotcherlakota
Date: Mon, 13 Apr 1992 01:02
Date: Mon, 13 Apr 1992 01:02
26 lines
976 bytes
976 bytes
Script gawk.bug:
#!/bin/csh
nawk \
'\
END { print "var1 = ", var1 }' \
/dev/null var1="nawk works"
awk \
'\
END { print "var1 = ", var1 }' \
/dev/null var1="awk works"
gawk \
'\
END { print "var1 = ", var1 }' \
/dev/null var1="gawk works"
What happens when I run the above test:
gawk.bug
var1 = nawk works
var1 = awk works # I had to hit Ctrl-D to force this message
gawk: var1=gawk works: No such file or directory
Question: Is this a known bug in gawk?
Please reply to hari@fai.fmiapd.com
Technical Details
Message-ID:
<1992Apr13.010240.15346@leland.Stanford.EDU>Path:
arc1-ca.pugleaf.net!sparky!uunet!cis.ohio-state.edu!leland.stanford.edu!harikShow Full Headers
Complete Article Headers
Newsgroups: gnu.utils.bug Path: arc1-ca.pugleaf.net!sparky!uunet!cis.ohio-state.edu!leland.stanford.edu!harik From: harik@leland.stanford.edu (Srihari Kotcherlakota) Subject: Passing variables to gawk doesn't work? Message-ID: <1992Apr13.010240.15346@leland.Stanford.EDU> Sender: gnulists@ai.mit.edu Organization: DSG, Stanford University, CA 94305, USA Distribution: gnu Date: Mon, 13 Apr 1992 01:02:40 GMT Approved: bug-gnu-utils@prep.ai.mit.edu Lines: 29