🚀 go-pugleaf

There is a difference in the way bash and sh handle "$@" in a
function.  Here is an example in sh:

    $ args () { for a in "$@"; do echo $a; done }
    $ args 1 2 3 4
    1
    2
    3
    4
    $

And the same example in bash:

    $ args () { for a in "$@"; do echo $a; done }
    $ args 1 2 3 4
    1 2 3 4
    $

I'm running on a Sun 3/60 with Sun UNIX 4.2 Release 3.5, and the ident
string in my bash is /bin/bash:

          $Id: gtest.c,v 1.10 88/07/02 13:34:45 afb Exp Locker: afb $

Does anyone have a fix?  Thanks,

Andy Bliven
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