🚀 go-pugleaf

In article <dqua.813429186@dqua>,
   dqua@earthlink.net (Derick J.R. Qua-Gonzalez) wrote:
>btrojano@chat.carleton.ca (Bart Trojanowski) writes:
>
>>I desperately need help.  My assignment is due very soon.
>
>This shouldn't be in c.l.c. But since you xposted to C++ as wel...
>
>>What I need to do is allocate memory for the following....
>>          float array[x][y];
>>but dinamicaly, ie the user specifies how large it must be.
>
>>float = **array; 
>       |
>       |
>     WHAT?
>
Hope my idea will help you! (No guarantees on correctness)
but...

If I understand your problem, you want to make a two dimensional array
of
floats by using new after you get the two indeces from the user?

user enters x and y(two ints)

if you declare array a pointer to a float...

float *array;

then use new as follows...
In c++...
array = new float[x*y]; 

In c...
array = (float*) malloc(sizeof(float)*x*y);

this should create an array of floats in memory which you can be used
like  this(I think)

array[a*y+b] where as array[a][b] is what you want.

float *array;
x = 3;
y = 4;
array = new float[x*y];

/* assign array[2][3] to be 3.14159 */
array[2*y + 3] = 3.14159;

in c++...
cout << "array[" << 2 << "][" << 3 << "] = " << array[2*y+3] << endl;
or 
cout << "array[2][3] = " << array[2*y+3] << endl;

in c...
printf("array[%d][%d] = %f\n", 2, 3, array[2*y + 3] );
or 
printf("array[2][3] = %f\n", array[2*y +3] );


output should be...
with printf in c I got
array[2][3] = 3.141590

with cout in c++ I got
array[2][3] = 3.14159

to work with array[a][b] in array[x][y] just use array[a*y+b]


Hope I didn't screw up somewhere.
Use this information at your own risk.

TechMan2@ix.netcom.com