Re: diofantea

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#35

From: Ignacio Larrosa Cañestro
Date: Mon, 07 Nov 2011 21:05

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superpollo wrote:
> superpollo ha scritto:
>> risolvere per x,y interi positivi:
>>
>> x^4/y = (y+4)*(y^2-1)*(y^2-4)*(y^2-9)
>
> hola! quieria extender el problema a e.c.m.


Multiplicando por y, con lo que no deberemos tener en cuenta las soluciones 
con y = 0, queda

x^4 = (y+4)(y+3)(y+2)(y+1)y(y-1)(y-2)(y-3)

La �nica posibilidad de que el producto de 8 enteros consecutivos sea cero, 
es que lo sea alguno de ellos, con lo que x = 0 y no hay soluciones 
positivas.


-- 
Saludos,

Ignacio Larrosa Ca�estro
A Coru�a (Espa�a)
ilarrosaQUITARMAYUSCULAS@mundo-r.com
http://www.xente.mundo-r.com/ilarrosa/GeoGebra/

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From: Ignacio Larrosa Cañestro <ilarrosaQUITARMAYUSCULAS@mundo-r.com>
Newsgroups: it.scienza.matematica,es.ciencia.matematicas
Subject: Re: diofantea
Date: Mon, 7 Nov 2011 22:05:52 +0100
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