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Article #37

Re: diofantea

#37
From: Ignacio Larrosa Cañestro
Date: Mon, 07 Nov 2011 21:25
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Ignacio Larrosa Ca�estro wrote:
> superpollo wrote:
>> superpollo ha scritto:
>>> risolvere per x,y interi positivi:
>>>
>>> x^4/y = (y+4)*(y^2-1)*(y^2-4)*(y^2-9)
>>
>> hola! quieria extender el problema a e.c.m.
>
>
> Multiplicando por y, con lo que no deberemos tener en cuenta las
> soluciones con y = 0, queda
>
> x^4 = (y+4)(y+3)(y+2)(y+1)y(y-1)(y-2)(y-3)
>
> La �nica posibilidad de que el producto de 8 enteros consecutivos sea
> cero,

quise decir "una cuarta potencia", no "cero".

> es que lo sea alguno de ellos, con lo que x = 0 y no hay
> soluciones positivas.

Saludos,

Ignacio Larrosa Ca�estro
A Coru�a (Espa�a)
ilarrosaQUITARMAYUSCULAS@mundo-r.com
http://www.xente.mundo-r.com/ilarrosa/GeoGebra/
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From: Ignacio Larrosa Cañestro <ilarrosaQUITARMAYUSCULAS@mundo-r.com>
Newsgroups: it.scienza.matematica,es.ciencia.matematicas
Subject: Re: diofantea
Date: Mon, 7 Nov 2011 22:25:17 +0100
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