Article View: it.scienza.matematica
Article #58Re: problema di quinta elementare
From: joseph cornelius hallenbeck
Date: Tue, 05 Mar 2013 17:41
Date: Tue, 05 Mar 2013 17:41
45 lines
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3513 bytes
Socratis ha scritto: > "joseph cornelius hallenbeck" <joseph@cornelius.hallenbeck> ha scritto nel messaggio >> Socratis ha scritto: >>> "joseph cornelius hallenbeck" ha scritto nel messaggio >>> >>>> Socratis ha scritto: >>>>> "gbaltius" <kaeelepian@aol.it> ha scritto nel messaggio >>>>>> Ecco un problema assegnato (per casa) in una quinta elementare. >>>>>> Inventa un problema in cui devi trovare la misura del raggio partendo dalla circonferenza. >>>>>> (parole vietate: Circonferenza, raggio, diametro). >>>>>> >>>>>> >>>>>> Confesso di non aver capito il significato di questo esercizio.. >>>>> A parte la difficolta' per una quinta elementare....... >>>>> Come si trova la circonferenza C, avendo il raggio r ? >>>>> La formula e' : C = 2r * pi >>>>> >>>>> quindi 2r = C/pi (2r=diametro) >>>>> r = C/2pi (formula inversa) >>>>> >>>>> es. per r=3 >>>>> C= 2r*pi = 18.849.. >>>>> r = 18.849../2pi = 3 >>>> e la tunze? >>> La tunze entra nella molt. fra le i e le unita' : >>> Invece di 0,2*2=0.4, dirai 2i*20i=40i che e' esattamente quello che tu >>> chiami 0,4 di 100i. >>> >>> In realta' 0,4 = 40i^2 >>> >>> Il problema e' che gli Standard negano, negate, che 1 != 1^2 >>> >>> In verita' non c'entra niente 1 con 1^2, meno che meno c'entra 1 con 1^3. >> grazie, ora e' tutto piu' chiaro > > Deo gratias...non sono pazzo....... ... > Mettiamo caso di avere 3 masse ciascuna da 0,5...... > Come definire la F, in base alla formula F= (m_1*m_2*m_3)) /d^2 ?? > Siamo sicuri che dev'essere d^2 e non d^3 ?? basta misurare, no? -- ho avuto un flirt con un topo, non ricordo i particolari
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From: joseph cornelius hallenbeck <joseph@cornelius.hallenbeck>
Newsgroups: it.scienza.matematica,free.it.scienza.fisica
Subject: Re: problema di quinta elementare
Date: Tue, 05 Mar 2013 18:41:08 +0100
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