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Article #336gr.9 problem
From: Nicole Smith
Date: Tue, 17 Nov 1992 17:11
Date: Tue, 17 Nov 1992 17:11
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1118 bytes
Our group is Nicole Smith,Dan Cooper,Pierre Mattar and we are in grade 9 at Rundle College in Calgary Alberta,Canada.
9 squared -9-9-9-9-9-9-9-9=9. 9 squared = 81 and when you subtract the remainder of the 9's your answer will be 9. This applies to any number except for the #1.
One of the 9's is squared and you subtract 8 of the 9's because you can only use nine 9's and one of them is been used already.If you square one of the #'s and subtract thje rest of the #'s it equals the # that you are <|D"i6F<DfYsfEN:w{W+2v%*>&]W"'$Zw0R=@6<@@b@yBT=6>[Ns>30U<:?MJk\l-~.
That is some of our solution.Bye dude
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Path: arc1-ca.pugleaf.net!sparky!uunet!psgrain!puddle!f49.n134.z1.fidonet.org!Nicole.Smith From: Nicole.Smith@f49.n134.z1.fidonet.org (Nicole Smith) Sender: ufgate@puddle.fidonet.org (newsout1.26) Newsgroups: k12.sys.channel2 Subject: gr.9 problem Message-ID: <20544.2B0A5A8D@puddle.fidonet.org> Date: Tue, 17 Nov 92 10:11:06 PDT Organization: FidoNet node 1:134/49 - The Student Exchang, Calgary Alta Lines: 9