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Article #3018Re: Floating point performance
From: Joe Buck
Date: Thu, 16 Oct 1986 16:56
Date: Thu, 16 Oct 1986 16:56
18 lines
1355 bytes
1355 bytes
In article <8575@lanl.ARPA> jlg@a.UUCP (Jim Giles) writes:
>Mflops:(Millions of FLoating point OPerations per Second)
>MHz: (Millions of cycles per second)
>
>Therefore 'Mflops per MHz':(Millions^2 FLoating point OPeration cycles per
> sec^2)
>
>Sounds like an acceleration to me. Must be a measure of how fast computer
>speed is improving. Still, the choice of units forces this number to
>be small. 8-)
You multiplied instead of dividing. If you had divided, you would
have found that the number measures floating point operations per
cycle.
--
- Joe Buck {hplabs,fortune}!oliveb!epimass!jbuck, nsc!csi!epimass!jbuck
Entropic Processing, Inc., Cupertino, California
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Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Path: arc1-ca.pugleaf.net!utzoo!mnetor!seismo!rutgers!sri-spam!nike!oliveb!epimass!jbuck From: jbuck@epimass.UUCP (Joe Buck) Newsgroups: net.arch Subject: Re: Floating point performance Message-ID: <531@epimass.UUCP> Date: Thu, 16-Oct-86 12:56:14 EDT Article-I.D.: epimass.531 Posted: Thu Oct 16 12:56:14 1986 Date-Received: Thu, 16-Oct-86 23:41:27 EDT References: <340@euroies.UUCP> <1989@videovax.UUCP> <722@mips.UUCP> <8184@sun.uucp> <8575@lanl.ARPA> Reply-To: jbuck@epimass.UUCP (Joe Buck) Organization: Entropic Processing, Inc., Cupertino, CA Lines: 18 Summary: Mflops/MHz == flops per cycle