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> Given a dimensioned fortran array A(50,300), I will set element
> A(10,100)=666, just so a unique value is present.  Now I pass the array
> to a c program via the argument list.  Given the column/row major
> differences, I can address the fortran element A(10,100) as
> *(apntr+9*300+99) and get the correct answer.  The hassle with this is
> that the dimensionality of the array must be known to the c program, ie.
> 300 must be known.

So far so good.

> Now, in C 2-d arrays are simply an array of pointers to a linear array.

Slight misconception here.  In C, multi-dimensional arrays are *not*
arrays of pointers to linear arrays.  See the declarations below:

    int a[2][3];                /* multi-dimensional array */
    int (*a[2]);                /* array of pointers to arrays of
                                   indefinite size */
    int (*a)[3];                /* pointer to array of indefinite size
                                   of arrays of 3 ints */

FORTRAN can express only the first notion (since FORTRAN lacks pointers).

The diference between C multi-dimensional arrays and FORTRAN
multi-dimensional arrays is that C arrays are stored in what is often
called "odometer order", while FORTRAN arrays are stored in
"anti-odometer order".  That is, the elements of the above declared
multi-dimensional array are stored in this order:

        a[0][0], a[0][1], a[1][2], a[1][0], a[1][1], a[1][2]

while the fortran array declared

        INTEGER A(2,3)

is stored in this order:

        A(1,1), A(2,1), A(1,2), A(2,2), A(1,3), A(2,3)

By the way, *(a+9*300+99) or a[9*300+99] to get at A(10,100) should
*NOT* have worked, since it assumes FORTRAN stores arrays in "odometer"
order.  (It also assumes that FORTRAN passes an array by placing the
address of the array on the stack in a C-compatible form, but his is
often the case, and is thus a "safe" assumption.) Anyway, what is needed
is a[9+50*99].

> My question is can I access the fortran array above as a double
> indirection + offset, as I would a C array?  Is there any way of
> accessing the array that does not need to know the dimensions to get the
> offset?  [Suggestions like 'do it in fortran' are not needed--thanks!!]

As indicated above, the C declaration "int a[3][2];" is "equivalent to"
the fortran "INTEGER A(2,3)", (where all appropriate indices are
swapped on references).  Thus, you should be able to do something like
this:

        FORTRAN main program:

                    INTEGER A(2,3)
                    CALL INIT(A)
                    DO 100 I=1,2
                        DO 90 J=1,3
                            PRINT *, A(I,J)
             90         CONTINUE
            100     CONTINUE
                    STOP
                    END

        C subroutine to initialize the array:

            void INIT(a) int a[3][2]; {
                int i,j,k=0;
                for(i=0;i<2;i+=1){
                    for(j=0;j<3;j+=1){
                        a[j][i] = ++k;
                    }
                }
            }

        And get the output I did, namely:

            1
            2
            3
            4
            5
            6

Now then, as to *implicitly* passing the "shape" of the array from
FORTRAN to C, there is no real way to do that.  The closest (even
somewhat portable) way I can see to do that is like so:

        INTEGER A(2,3)
        CALL CSUBR(A,2)
        ...

        void CSUBR(a,n) int a[], *n; {
            ... a[i+(*n)*j] ...; /* access FORTRAN array element A(i+1,j+1) */
        }

Which corresponds closely to the usual FORTRAN idiom of

        INTEGER A(2,3)
        CALL FSUBR(A,2,3)
        ...

        SUBROUTINE FSUBR( A, N, M )
        INTEGER A(N,M)
            ... A(I,J) ...      ! access FORTRAN array element A(I,J)

So...   why don't you do it in FORTRAN?     :-)

> Dave Carlson
> {allegra,seismo,decvax}!rochester!ur-valhalla!dave
-- 
Wayne Throop at Data General, RTP, NC
<the-known-world>!mcnc!rti-sel!rtp47!throopw