Thread View: net.lang.forth
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1 total messages
Started by Rick Peralta
Fri, 06 Sep 1985 14:21
sqrt
Author: Rick Peralta
Date: Fri, 06 Sep 1985 14:21
Date: Fri, 06 Sep 1985 14:21
35 lines
1074 bytes
1074 bytes
This is'nt really quick or smart, but I think it works for most cases.
N - the number to find the root of.
R - resolution of the answer.
I - latest increment.
V - latest value to test.
sqrt(N)
{
R = .01
I = N / 2
V = I
if (N < 0) barf
loop:
I = N / 2
if ( (V*V) > N+R )
{
V = V - I
goto loop
}
else
if ( (V*V) < N-R )
{
V = V + I
goto loop
}
return V
}
Sorry for the pseudo code, I don't speak forth too well.
Rick ...!cybvax0[!dmc0]!fbp
"Life is a compromise"
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