🚀 go-pugleaf

> According to the *BM DOS technical reference, disk cluster addresses are
> 12 bits under MsDos 2.x and 16 bits under 3.x.  Does this mean that if
> I got 3.x for my 6300 with a 20 Mbyte hard disk and reformatted, I would
> go from 8K clusters to .5K-2K (somewhere in that range, I calculated)
> clusters?  The reason I'm wondering is that I have 500+ files currently.
> Some numbers:
>         8192 bytes/cluster implies 4096 bytes waste/file
>         4096 bytes/file * 500 files is about 2 Mbyte of
>         waste due to internal fragmentation.
> Obviously, I'd like to reduce the waste that results from the 8K cluster
> size.  Does anyone know if my assumptions are true, and if so, whether or
> not 3.1 (preferably; I hear 3.0 and 3.2 are bug-ridden) is available for
> the 6300?  If it is available, I'd need an address to which I could send
> a purchase order - my organization doesn't believe in money :-).
> 
> Please email; if there exists enough interest, I'll summarize and post.
> Thanx ---                      \scott
> -- 
> Scott Hazen Mueller                         lll-crg.arpa!csustan!smdev
> City of Turlock                             work:  (209) 668-5590 -or- 5628
> 901 South Walnut Avenue                     home:  (209) 527-1203
> Turlock, CA 95380                           <Insert pithy saying here...>

Sorry to break the news, but the folks at AT&T & Microsoft made a mistake
on the AT&T MS-DOS 3.1.  If You format your 6300 PC with a 20M HD with
AT&T MS-DOS 3.1 format command, you'll still get 8k cluster size.  There's
at least one way to format the 20M HD on the 6300 with IBM PC-DOS 3.1 to
get 2k cluster size, then you can not boot from the hard disk, because of
different boot sector location I presume.

If you can make the 6300 PC with 20M HD to boot from the HD and having
2k cluster size, the people at AT&T's HOTLINE would love to hear from you.

	John N. Le (AT&T Consumer Products Laboratories, Indpls, IN)
	..!inuxh!jnl

	John