🚀 go-pugleaf

1) "a decimal constant whose value exceeds the largest signed machine
integer is taken to be long", according to K&R.  Thus, BIG is long if ints
are 16 bits.

2) the assignment "i = BIG" will lose accuracy if an int is shorter than
a long.  if accuracy is lost, then after the assignment, BIG is really
not equal to i.

3) in the comparison "i == BIG", the "usual arithmetic conversions"
are done.  if BIG is long, then i will be converted to long.  however,
if accuracy was lost, there is of course no way to regain it.

thus, the "unexpected" results of the original posting would really
be "expected", on a closer reading of K&R.

	jeff dean, cdp!jeff