🚀 go-pugleaf

On Wed, 20 Jul 2005 19:39:55 -0700, "ScottW" <ScottW48@hotmail.com>
wrote:

>
>"Howard Ferstler" <ferstle@attglobal.net> wrote in message 
>news:42DEEDA5.4B56E56@attglobal.net...
>> Stewart Pinkerton wrote:
>>>
>>> On 19 Jul 2005 09:49:34 -0700, "ScottW" <ScottW48@hotmail.com> wrote:
>>>
>>> >
>>> >
>>> >Stewart Pinkerton wrote:
>>> >> On Mon, 18 Jul 2005 17:00:48 -0400, Howard Ferstler
>>> >> <ferstle@attglobal.net> wrote:
>>> >>
>>> >> >Trevor Wilson wrote:
>>> >>
>>> >> >> You STILL deny that I was correct, in spite of the fact that NOT
>>> >> >> ONE SINGLE poster has supported your nonsensical stance. Not Arny, 
>>> >> >> not Dick
>>> >> >> Pierce, no one. You're out on a limb and completely out of your 
>>> >> >> gourd.
>>> >> >
>>> >> >It is likely that I misunderstood the individual's problem.
>>> >> >However, I still hold that a near short in parallel with a
>>> >> >speaker will render that speaker mute, no matter what the
>>> >> >protection circuits are doing.
>>> >>
>>> >> Well, you're just plain wrong.
>>> >
>>> >Define near short and define mute.
>>> >
>>> >It will probably put most amps into current limit.
>>>
>>> But not all................. :-)
>>>
>>> >> >In any case, a super-expensive amp (like that Krell) is an
>>> >> >overpriced item that appeals to suckers.
>>> >
>>> > A Krell KSA will blow that short like a fuse :)  Instant repair.
>>>
>>> Quite so! :-)
>>>
>>> Even if the near short is current-capable, the Krell will still
>>> provide enough current to drive both the short and the speaker. Since
>>> they're in parallel, there won't be any reduction of voltage (and
>>> hence volume) to the speaker. Shame that Howard doesn't understand
>>> this.
>>
>> How can any current be flowing through the speaker? All of
>> it will be passing through the short in parallel.
>>
>> Howard Ferstler
>
>The only way the current through the speaker is zero is
>if the voltage across the speaker is zero or the speaker
>is fried and has infinite impedance.
>We'll assume the speaker is ok.
>Since the speaker and the short are in parallel..
>they will both have the same voltage across them.
>
>Clearly the current required to generate a voltage
>across a true zero ohm short is infinite  (I = V/R)... but a true
>zero ohm short is physically impossible (well maybe the
>superconductor guys have something close).

Actually, not close, but absolutely zero resistance - that's the whole
point!
>
>So... if the amp hasn't shut down and is producing a voltage
>at all across the short (which isn't really a perfect short)
>... the same voltage will be present
>across the speaker and current will flow thru the speaker.

Quite so. Ferstler is an incompetent - but we knew that.
-- 

Stewart Pinkerton | Music is Art - Audio is Engineering