🚀 go-pugleaf

Well I don't remember who originally asked for a simple way to extract the 
center channel from distince left and right channels but here is what I have
came up with:

Okay, lets forget about math for a while and concentrate on what we want.
Suppose , we are watching Jonny Carson again and he is the only one talking
at the moment. Instead of having half of his voice out the right channel and
half out the left, we want him to sound out a third speaker at the center.
At this instant, we probably want the side speakers to mute for clarity.
However, anytime someone else who is not at the center speakes, we want the
center speaker off and the side speakers back on. So , the following
logic applies:
let A equals L +.5M, B equals R + .5M,  and X equal a control signal produced
by A and B to  control A and B. 0 is no signal, ED is ED Mc'man , Other is
the other guy on the opposite side of ED, and Jon is of course Jonny
 				we have:
A     B      X
--------------
0     0      0             any EE majors out there will recognize the
ED    0      0       	   table to be that of an AND gate. An AND
0     Other  0             gate can be represent mathematicly as 
Jon   Jon    Jon	   
					X = AB

So, the answer is to take the channels and MULTIPLY them together.
This creates a control  signal suitable for turning the A + B (which is
MONO) signal on or off at the appropriate time. Of course, we must have a 
circuit of sufficiently fast response so that only a very small time period
is compared by the circuit at any given time. For something to start with,
try digging up some basic digital circuit books and look up simple diode 
implimentation of the AND gate. Then replace the diodes with high value
resistors.
	There you have it folks, either I am half right or half left...
I mean half right or totally wrong about this  so don't FLAME too much if
it turns out to be another smart aleck answer...
(ps, I hope this gets at least past the modem line I am calling on as this
is my very 1st post on this system)

Chris