🚀 go-pugleaf

Hello,
	I was asking about throw height for numbers.  I
	compared shower height to that of cascade.  With the
	assumption (suggested by Jack Boyce  a while back)
	that your dwell time is such that you release a ball
	just as one lands in the other hand.  I have calculated
	the height for the two patterns.

Height_cascade = ((b-1)/tr)^2  [feet]
Height_shower  = 4*((b-1)/tr)^2 [feet]

where:
o tr = throw rate [thows per second]
o b = number of balls being juggled
o I am assuming g = 32 ft/s/s because strangly enough the
  numbers work better using U.S. Customary Units for this.
o I am also asuming that the launch and land elevations are
  equivalent. 

	I find that my maximum controllable throw rate is 3 throws per second,
	based on my 4 foot high 71 (that is doing it standing
	in a 8 foot ceiling room and just squeezing it in = 4 feet)
	so for example:

tr=3 thows per second
b=5 balls

Height_cascade = ((5-1)/3)^2  [feet] = 1.78 feet (*) ss = 5
Height_shower  = 4*((5-1)/3)^2 [feet]= 7.11 feet     ss = 91

	So no wonder I can't shower 5 in my appartment :)
	I think this (*) sounds about right because my tightest
	5 ball cascade is about that high.
	Also, from the above, a 51 is the same height as a 5
	or a 71 a 7.

	I guess if ceilings weren't so low there would be
	more numbers jugglers out there :^}. 

-Eddie Frie WSU Juggling Club