🚀 go-pugleaf

Got my A's and B's mixed up there. Here's the correction in the construction
of the inverse of a point C with respect to a circle of radius AB:

	.________.________.
	A        B        C

>    Draw a circle centred at A, radius AB. Use C as centre and mark points
>    P and P' on the circumference of this circle, by drawing an arc with 
>    radius CA. Now draw arcs centred at P and P' respectively, with radius
>    PB. These arcs will intersect at 2 points, one is B itself, the
>    other is the point D which is the bisection point you are looking for.
>    For proof, consider the similar triangles APC and CPD, and remember the
>    definition of the inverse point.

Draw a circle centred at A, radius AB. Use C as centre and mark points
P and P' on the circumference of this circle, by drawing an arc with 
radius CA. Now draw arcs centred at P and P' respectively, with radius
PA. These arcs will intersect at 2 points, one is A itself, the
^^                                                ^
other is the point D which is the bisection point you are looking for.
For proof, consider the similar triangles APC and APD, and remember the
                                                  ^
definition of the inverse point.

Vivek Rau
vivekr@osc.com