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Article #2680

Re: closed form for a sum (SPOILER)

#2680
From: Daniel A. Asimov
Date: Wed, 13 Jan 1993 02:31
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In article <1iv1enINNnq6@master.cs.rose-hulman.edu> goddard@NeXTwork.Rose-Hulman.Edu (Bart E. Goddard) writes:
>
>Evaluate: 
>        \infinity 
>          ___
>         \        sin(n)/n
>         /___
>         n = 1
>The solution is nice.
>--
>Bart Goddard                            |Behold, thy King cometh unto thee,
>Math. Dept. Rose-Hulman Inst. of Tech.  |meek, and sitting upon an ass, and
>goddard@nextwork.rose-hulman.edu        |a colt, the foal of an ass.


The sum is (pi - 1)/2.

(Sketch):  Identify the sum as the imaginary part of sum (exp(in)/n).
Consider sum (z^n/n) and e.g. by differentiating this, identify it with
log(1/(1-z)). Now plug in exp(in) for z, take the imaginary part, and
use the half-angle formula to see that it is (pi-1)/2.


Dan Asimov
Mail Stop T045-1
NASA Ames Research Center
Moffett Field, CA 94035-1000

asimov@nas.nasa.gov
(415) 604-4799
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From: asimov@wk223.nas.nasa.gov (Daniel A. Asimov)
Subject: Re: closed form for a sum (SPOILER)
References: <1iv1enINNnq6@master.cs.rose-hulman.edu>
Sender: news@nas.nasa.gov (News Administrator)
Organization: NAS, NASA Ames Research Center, Moffett Field, California
Date: Wed, 13 Jan 93 02:31:58 GMT
Message-ID: <1993Jan13.023158.24029@nas.nasa.gov>
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